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In an organ pipe ( may be closed or open...

In an organ pipe ( may be closed or open of `99 cm` length standing wave is setup , whose equation is given by longitudinal displacement `xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos 2 pi (400) t`
where `y` is measured from the top of the tube in metres and `t` in second. Here `1 cm` is th end correction.

The air column is vibrating in

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In an organ pipe ( may be closed or open of 99 cm length standing wave is setup , whose equation is given by longitudinal displacement xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos 2 pi (400) t where y is measured from the top of the tube in metres and t in second. Here 1 cm is th end correction. Assume end correction approximately equals to (0.3) xx (diameter of tube) , estimate the moles of air pressure inside the tube (Assume tube is at NTP , and at NTP , 22.4 litre contain 1 mole)

In an organ pipe ( may be closed or open of 99 cm length standing wave is setup , whose equation is given by longitudinal displacement xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos 2 pi (400) t where y is measured from the top of the tube in metres and t in second. Here 1 cm is th end correction. Assume end correction approximately equals to (0.3) xx (diameter of tube) , estimate the moles of air pressure inside the tube (Assume tube is at NTP , and at NTP , 22.4 litre contain 1 mole )

In an organ pipe ( may be closed or open of 99 cm length standing wave is setup , whose equation is given by longitudinal displacement xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos 2 pi (400) t where y is measured from the top of the tube in metres and t in second. Here 1 cm is th end correction. Assume end correction approximately equals to (0.3) xx (diameter of tube) , estimate the moles of air pressure inside the tube (Assume tube is at NTP , and at NTP , 22.4 litre contain 1 mole )

In an organ pipe (may be closed or open ) of 99 cm length standing wave is set up , whose equation is given by longitudinal displacement. xi = (0.1 mm) cos ( 2pi)/(0.8) (y + 1 cm) cos (400) t where y is measured from the top of the tube in metres and t "in" seconds . Here 1 cm is the end correction. Equation of the standing wave in terms of excess pressure is ( take bulk modulus = 5 xx 10^(5) N//m^(2) ))

In an organ pipe (may be closed or open ) of 99 cm length standing wave is set up , whose equation is given by longitudinal displacement. xi = (0.1 mm) cos ( 2pi)/(0.8) (y + 1 cm) cos (400) t where y is measured from the top of the tube in metres and t "in" seconds . Here 1 cm is the end correction. Equation of the standing wave in terms of excess pressure is ( take bulk modulus = 5 xx 10^(5) N//m^(2) ))

In an organ pipe (may be closed or open ) of 99 cm length standing wave is set up , whose equation is given by longitudinal displacement. xi = (0.1 mm) cos ( 2pi)/(0.8) (y + 1 cm) cos (400) t where y is measured from the top of the tube in metres and t "in" seconds . Here 1 cm is the end correction. The upper end and the lower end of the tube are respectively .

In an organ pipe (may be closed or open ) of 99 cm length standing wave is set up , whose equation is given by longitudinal displacement. xi = (0.1 mm) cos ( 2pi)/(0.8) (y + 1 cm) cos (400) t where y is measured from the top of the tube in metres and t "in" seconds . Here 1 cm is the end correction. The upper end and the lower end of the tube are respectively .

In an organ pipe (may be closed or open ) of 99 cm length standing wave is set up , whose equation is given by longitudinal displacement. xi = (0.1 mm) cos ( 2pi)/(0.8) (y + 1 cm) cos (400) t where y is measured from the top of the tube in metres and t "in" seconds . Here 1 cm is the end correction. The upper end and the lower end of the tube are respectively .