(x)/(y)(a+b)^(2)x^(2)-4abx-(a-b)^(2)=0

Solve by factorization: (a+b)^(2)x^(2)-4abx-(a-b)^(2)=0

Solve the following equation by using the method of factorization: (a+b)^2x^2-4abx-(a-b)^2=0

In each of the following,determine whether the given values are solutions of the given equation or not: 2x^(2)-x+9=x^(2)+4x+3,x=2,x=3 (ii) -sqrt(2)x-4=0,x=-sqrt(2),x=-2sqrt(2) (iii) a^(2)x^(2)-3abx+2b^(2)=0,x=a/b,x=b/a

abx^(2)+(b^(2)-ac)x-bc=0

If the polynomial (a^(2)-b^(2))x^(2)+2abx+(a^(2)+b^(2))a,b,c are constants, be a linear polynomial, then prove that a = b.

A tangent at a point on the circle x^(2)+y^(2)=a^(2) intersects a concentric circle C at two points P and Q. The tangents to the circle X at P and Q meet at a point on the circle x^(2)+y^(2)=b^(2). Then the equation of the circle is x^(2)+y^(2)=abx^(2)+y^(2)=(a-b)^(2)x^(2)+y^(2)=(a+b)^(2)x^(2)+y^(2)=a^(2)+b^(2)

Solve by factorization: a^(2)x^(2)-3abx+2b^(2)=0

sqrt(a^(2)x^(2)+2abx+b^(2)) = ……………..

The roots of the equation 2a^(2)x^(2) - 2abx + b^(2) = 0 when a lt 0 and b gt 0 are :

Solve the equation a^(2)x^(2)-3abx+2b^(2)=0 by the method of completing the square.