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Fe^(2+) and Fe^(3+) can be distinguished...

`Fe^(2+) and Fe^(3+)` can be distinguished by

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Assertion : The blue precipitate formed by the action of K_(4)[Fe(CN)_(6)] on Fe^(3+) and by that of K_(2)[Fe(CN)_(6)] on Fe^(2+) have the same composition Reasion : [Fe(CN)_(6)]^(3-) oxides Fe^(2+) to Fe^(3-) and itself gets reduced to [Fe(CN)_(6)]^(4-) .

Standard electrode potentials are Fe^(2+)//Fe, E^(@) = -0.44 V Fe^(3+)//Fe^(2+), E^(@) = +0.77 V If Fe^(3+), Fe^(2+) , and Fe block are kept together, then

Standard electrode potentials are Fe^(2+)//Fe, E^(@) = -0.44 V Fe^(3+)//Fe^(2+), E^(@) = -0.77 V If Fe^(3+), Fe^(2+) , and Fe block are kept together, then