A spectral line in the spectrum of H atom has a wavelength of `15222.22 cm^(-1)` .The transition responsible for this rediation is (Rydherg constant `R = 10977 cm^(-1)`

A spectral line in the spectrum of H atom has a wave number of 1522.222 cm^(-1) .The transition responsible for this radiation is (Rydberg constant R = 10977 cm^(-1)

A spectral line in the Lyman series of hydrogen atom has a wave number of 82200 cm^(-1) .What transition is resposible for the radiation ? (R = 109600 cm^(-1))

A spectral line in the Balmer series of hydrogen spectrum corresponds to wavelength 6561Å. Find the energy levels involved in the transition responsible for the origin of this line (R=109679cm^(-1)) .

The wavelength (in cm) of second line in the Lyman series of hydrogen atomic spectrum is (Rydberg constant =" R cm"^(-1) )

Wavelength of a spectral line found in the atomic spectrum of hydrogen is 4861 Å . Between which two quantum states does the transition of electron occur to generate this line ? Rydberg constant = 1.097xx 10^(7) m^(-1) .

Bohr was the first to explain the structure of hydrogen atom and spectrum. Calculate the wavelength of the first line in the Lyman series of the hydrogen spectrum. ( R= 109677 cm^(-1))

The wave number of first line in Balmer series of hydrogen spectrum is (Rydberg constant, R_H = 109,678 cm^-1 ) nearly

The spectral line observed at 434 nm in the Balmer series of the hydrogen spectrum corresponds to a transition of an electron from the nth orbit. What is the value of n? [Rydberg constant, (R_(H))=109677cm^(-1) ]