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|[-2a,a+b,a+c],[b+a,-2b,b+c],[c+a,c+b,-2...

|[-2a,a+b,a+c],[b+a,-2b,b+c],[c+a,c+b,-2c]|=4(a+b)(b+c)(c+a)

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Show that A=|{:(-2a,a+b,c+a),(a+b,-2b,b+c),(c+a,c+b,-2c):}|=4(a+b)(b+c)(c+a)

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-2a,a+b,a+c(a+b)(b+c)(c+a),b+a,-2b,b+cc+a,c+b,-2c]|=

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