`56-:7*8(3)/(8)+5`

Simpilfy: 8(5)/(6)-3(3)/(8)+2(7)/(12)

The numerical expression (3)/(8) +((-5))/(7)=(-19)/(56) shows that

The arrangement of rational numbers (-7)/(10),(5)/(-8),(2)/(-3) in ascending order is (2)/(-3),(5)/(-8),(-7)/(10) (b) (5)/(-8),(-7)/(10),(2)/(-3) (c) (-7)/(10),(5)/(-8),(2)/(-3)(d)(-7)/(10),(2)/(-3),(5)/(-8)

Show that 3/4 + (3.5)/(4.8)+ (3.5.7)/(4.8.12)+ …… = sqrt8 -1

Evaluate : (iv) (3)/(8)+(-5)/(12)+(3)/(7)+(3)/(12)+(-5)/(8)+(-2)/(7)

Prove that: sin((3pi)/(8)-5)cos((pi)/(8)+5)+cos((3pi)/(8)-5)sin((pi)/(8)+7)=1

(-8)^(7//5)xx(-8)^(-4//5)xx(-8)^(-3//5) =

7/5 xx((-3)/8) + 3/4 xx 7/5

cos ((pi) / (8)) cos ((3 pi) / (8)) cos ((5 pi) / (8)) cos ((7 pi) / (8)) =