Two parallel S.H.M.s have equations `y_1=A_1sin(omegat+2pi)` and `y_2=A_2sin(omega/t+4pi)`. The amplitude of the resultant motion is

Two parallel S.H.M.s have equations y_1=A_1sin(omegat+2pi) and y_2=A_2sin(omegat+4pi) . The amplitude of the resultant motion is

A particle is subjected to SHM as given by equation x_1=Asinomegat and x_2=A_2sin(omegat+(pi)/(3)) . The maximum acceleration and amplitude of the resultant motion are a_(max) and A , respectively Then.

A particle is subjected to SHM as given by equations x_1 = A_1 sin omegat and x_2 = A_2 sin (omega t + pi//3) .The maximum acceleration and amplitude of the resultant motion are it a_("max") and A ,respectively , then

The displacement of the interfering light waves are y_1 = 4 sin omegat and y_2 = 3 sin (omegat + pi//2) . The amplitude of the resultant wave is

Equations of two light waves are y_(1) = 4 sin omega t and y_(2) = 3 sin (omega t + (pi)/(2)) . What is the amplitude of the resultant wave as they superpose on each other?

The equation of simple harmonic motion of two particle is x_1=A_1" "sin" "omegat and x_2=A_2" "sin(omegat+prop) . If they superimpose, then the amplitude of the resultant S.H.M. will be

The equation of simple harmonic motion of two particle is x_1=A_1" "sin" "omegat and x_2=A_2" "sin(omegat+prop) . If they superimpose, then the amplitude of the resultant S.H.M. will be

The displacement of two interfering light waves are given by y_(1)=3 sinomegat,y_(2)=4 sin(omegat+pi//2) . The amplitude of the resultant wave is