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" 1."(cos20^(@)+8sin70^(@)sin50^(@)sin10...

" 1."(cos20^(@)+8sin70^(@)sin50^(@)sin10^(@))/(sin^(2)80^(@))" is equal to: "

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(cos20^(0)+8sin70^(0)sin50^(@)sin10^(0))/(sin^(2)80^(@)) is equal to

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sin10^(@)+sin20^(@)+sin40^(@)+sin50^(@)=sin70^(@)+sin80^(@)