For the equilibrium system :
`CO(g)+2H_2(g)hArr CH_3OH(l)` what is `K_c`?

Consider the equilibrium set up : 2H_(2(g))+CO_((g))hArrCH_(3)OH_((g)) What will be the effect of the following on the equilibrium of the reaction ? (i) Addition of H_(2) (ii) Addition of CH_(3)OH (iii) Removal of CO (iv) Removal of CH_(3)OH

Consider the equilibrium set up : 2H_(2(g))+CO_((g))hArrCH_(3)OH_((g)) What will be the effect of the following on the equilibrium of the reaction ? (i) Addition of H_(2) (ii) Addition of CH_(3)OH (iii) Removal of CO (iv) Removal of CH_(3)OH

The partial pressure of CH_3OH(g) , CO(g) and H_2(g) in equilibrium mixture for the reaction, CO(g) + 2H_2(g) hArr CH_3OH(g) are 2.0,1.0 and 0.1 atm respectively at 427^Oc. The value of K_p for the decomposition of CH_3OH to CO and H_2 is :

For the reaction : CO(g)+2H_(2)(g)hArr CH_(3)OH(g)

Describe the effect of: removal of CH_(3)OH on the equilibrium of: 2H_(2)(g)+CO(g)hArr CH_(3)OH(g) .

For the equilibrium 2H_(2)O(g) hArr 2H_(2)(g)+O_(2)(g) , equilibrium constant is K_(1) For the equilibrium 2CO_(2)hArr 2CO(g)+O_(2)(g) , equilibrium constant is K_(2) The equilibrium constant for : CO_(2)(g)+H_(2)(g)hArr CO(s)+H_(2)O(g) is :

Decribe the effect of : addition of CH_(3)OH on the equilibrium of the reaction 2H_(2)(g)+CO(g) hArr CH_(3)OH(g)

Decribe the effect of : removal of CO on the equilibrium of the reaction 2H_(2)(g)+CO(g) hArr CH_(3)OH(g)