Without using trigonometric tables, evaluate each of the following: `(sin^2 20^0+sin^2 70^0)/(cos^2 20^0+cos^2 70^0)+(sin(90^0-theta)sintheta)/(tantheta)+(cos(90^0-theta)costheta)/(cottheta)` +`cos(40^0+theta)-sin(50^0-theta)+(cos^2 40^0+cos^2 50^0)/(sin^2 40^0+sin^2 50^0)`

Without using trigonometric tables,evaluate each of the following: (sin^(2)20^(@)+sin^(2)70^(@))/(cos^(2)20^(0)+cos^(2)70^(@))+(sin(90^(@)-theta)sin theta)/(tan theta)+(cos(90^(@)-theta)cos theta)/(cot theta)+cos(40^(0)+theta)-sin(50^(@)-theta)+(cos^(2)40^(0)+cos^(2)50^(@))/(sin^(2)40^(0)+sin^(2)50^(@))

(2cos 40^0-cos 20^0)/(sin 20^0)=

(sin^(2) 20^(@) + sin^(2) 70^(@))/(cos^(2) 20^(@) + cos^(2) 70^(@)) + [ (sin (90^(@) - theta).sin theta)/(tan theta) + (cos (90^(@) - theta).cos theta)/(cot theta) ] .

Without using trigonometric tables , evaluate the following : (cot(90^(@)-theta)*sin(90^(@)-theta))/(sintheta)+(cot40^(@))/(tan50^(@))-(cos^(2)20+cos^(2)70^(@))

Without using trigonometric tables , evaluate the following : (cot(90^(@)-theta)*sin(90^(@)-theta))/(sintheta)+(cot40^(@))/(tan50^(@))-(cos^(2)20+cos^(2)70^(@))

Prove that : (sinthetacos(90^0-theta)costheta)/(sin(90^0-theta))+(costhetasin(90^0-theta)sintheta)/(cos(90^0-theta))=1

Without using trigonometric tables, evaluate each of the following: (-tanthetacot(90^0-theta)+secthetacos e c(90^0-theta)+sin^2 35^0+sin^2 55^0)/(tan10^0tan20^0tan30^0tan70^0tan80^0)

Without using trigonometric tables, evaluate each of the following: (-tanthetacot(90^0-theta)+secthetacos e c(90^0-theta)+sin^2 35^0+sin^2 55^0)/(tan10^0tan20^0tan30^0tan70^0tan80^0)

(cos^(2)theta)/(sin theta)-cosec theta+sin theta=0

The value of (cos(90^0-theta)sec(90^0-theta)tantheta)/(cos e c(90^0-theta)sin(90^0-theta)cot(90^0-theta))+(tan(90^0-theta))/(cottheta)"i s" 1 (b) -1 (c) 2 (d) -2