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0.2 + 0.22 + 0.222 + …….. to n terms =...

`0.2 + 0.22 + 0.222 + ……..` to `n` terms =

A

`(2/9) - (2/81)(1 - 10^(-n))`

B

`n - (1/9)(1 - 10^(-n))`

C

`(2/9)[n - (1/9)(1 - 10^(-n))]`

D

`2/9`

Text Solution

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The correct Answer is:
C
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NEW JOYTHI PUBLICATION-SEQUENCES AND SERIES -QUESTIONS FROM COMPETITIVE EXAMS
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