The magnetic dipole moment of earth is `6*4xx10^(21)Am^2`. If we consider it to be due to a current loop wound around the magnetic equator of the earth, then what should be the magnitude of the current? Take earth to be a sphere of radius `6400km`.

Assuming that the earth's magnetic field is due to large circular loop of current in the interior of the earth, what is the plane of the loop and what is the direction of current around it?

The earth's magnetic field may be considered to be due to a short magnet placed at the centre of the earth and oriented along the magnetic south-north direction. the ratio of the magnitude of the magnetic field on the earth's surface of magnetic equator to that at the magnetic poles

The magnetic moment of a circular current loop is 2.3 xx10^(-5) Am^(2) . What is the magnitude of the magnetic field on the axis of the loop at a distance of 1 cm from the loop?

The earth's magnetic field may be considered to be due to a short magnet placed at the centre of the earth annd oriented along the magnetic south-north direction. The ratio of the magnitude of the magnetic field on the earth's magnetic equator to that at the magnetic poles is

The magnetic field at a point on magnetic equator is 3*1xx10^-5T . If radius of earth is taken as 6400km , what is magnetic moment of the assumed dipole at the centre of earth?

The magnetic moment of the assumed dipole at the earth's centre is 8.0 xx 10^22 A m^2 . Calculate the magnetic field B at the geomagnetic poles of the earth. Radius of the earth is 6400 km .

The magnetic moment of the assumed dipole at the earth's centre is 8.0 xx 10^22 A m^2 . Calculate the magnetic field B at the geomagnetic poles of the earth. Radius of the earth is 6400 km .