The curve `y=f(x)=ax^(3)+bx^(2)+cx` is inclined at `45^(@)` to positive direction of x -axis at (0,0), but it touches x -axis at (1,0) then value of `((f''(1)*f''(2))/(2f(2)))` is

The curve y=ax^(3)+bx^(2)+cx is inclined at 45^(@) to x-axis at (0,0) but it touches x-axis at (1,0) , then

If the curve y=ax^(3) +bx^(2) +c x is inclined at 45^(@) to x-axis at (0, 0) but touches x-axis at (1, 0) , then

The curve y=ax^(3)+bx^(2)+cx is inclined at 45^(@) to x-axis at (0,0) but it touches x-axis at (1,0) , then a+b+c+10 is

The curve y=ax^(3)+bx^(2)+cx is inclined by 45^(@) to x-axis at origin and it touches x-axis at (1,0). Then

A polynomial ax^(3)+bx^(2)+cx+d in xy -plane intersects x -axis at (1,0) and (-1,0) and y -axis at (0,2) .The value of b is :

For a cubic function y=f(x),f'(x)=4x at each point (x,y) on it and it crosses the x- axis at (-2,0) at an angle of 45^(@) with positive direction of the x -axis.Then the value of (f(1))/(5)| is

The curve y = ax ^(3) + bx ^(2) + cx + 5 touches the x-axis at P (-2, 0) and cuts the y-axis at a point Q where its gradient is 3, then 2a + 4b is equal to :

Let f (x) =x ^(2) + bx + c AA in R, (b,c, in R) attains its least value at x =- and the graph of f (x) cuts y-axis at y =2. The value of f (-2) + f(0) + f(1)=