If area of the ellipse `(x^(2))/(16)+(y^(2))/(b^(2))=1` inscribed in a square of side length `5sqrt(2)` is A then A equals to ( take `pi=3.14`)

If area of the ellipse (x^(2))/(16)+(y^(2))/(b^(2))=1 inscribed in a square of side length 5sqrt(2) is A, then (A)/(pi) equals to :

The area of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is

Area of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is pi ab

If the ellipse (x^(2))/(a^(2)-7)+(y^(2))/(13-5a)=1 is inscribed in a square of side length sqrt(2)a, then a is equal to (6)/(5)(-oo,-sqrt(7))uu(sqrt(7),(13)/(5))(-oo,-sqrt(7))uu((13)/(5),sqrt(7),) no such a exists

If the ellipse x^2/a^(2)+y^2/b^(2)=1 is inscribed in a rectangle whose length to breadth ratio is 2 :1 then the area of the rectangle is

If the area of the ellipse ((x^(2))/(a^(2)))+((y^(2))/(b^(2)))=1 is 4 pi, then find the maximum area of rectangle inscribed in the ellipse.

If a quadrilateral is formed by four tangents to the ellipse (x^(2))/(9)+(y^(2))/(4)=1 then the area of the square is equal to

A square is inscribed inside the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1, the length of the side of the square is