The battery of EMF 5V and internal resistance `20Omega `is connected with a resistance `R_(1)`=`50Omega` and a resistance . A voltmeter of resistance `1000Omega` is used to measure the potential difference across `R1` .What percentage error is made in the reading.

A battery of emf 2V and internal resistance 0.5(Omega) is connected across a resistance in 1 second?

A battery having e.m.f. 5 V and internal resistance 0.5 Omega is connected with a resistance of 4.5 Omega then the voltage at the terminals of battery is

Two resistance of 400 Omega and 800 Omega are connected in series with 6 volt battery of negligible internal resistance. A voltmeter of resistance 10,000 Omega is used to measure the potential difference across 400 Omega . The error in measurement of potential difference in volts approximatley is

A voltmeter resistance 500 Omega is used to measure the emf of a cell of internal resistance 4 Omega . The percentage error in the reading of the voltmeter will be

A voltmeter resistance 500 Omega is used to measure the emf of a cell of internal resistance 4 Omega . The percentage error in the reading of the voltmeter will be

A battery of EMF 1.4 V and internal resistance 2Omega is connected to resistor of 100Omega resistance through an ammeter. The resistance of the ammeter is (4)/(3)Omega . A voltmeter is also connected to find potential difference across resistor. The ammeter reacds 0.02 A if resistance of voltmeter is 100x then x is

A battery of emf 5V and internal resistance 20Omega is connected to a combination of two resistance 50Omega and 40Omega in series. If the p.d. across the 50Omega resistor is measured by a voltmeter of resistance 1000Omega , what will be the percentage error?

A voltmeter with resistance 500Omega is used to measure the emf of a cell of internal resistance 4Omega .The percentage error in the reading of the voltmeter will be