Let y=g(x) be the image of f(x)=x+sin x ...

Let y=g(x) be the image of `f(x)=x+sin x` about the line `x+y=0` .If the area bounded by y=g(x) ,x-axis, x=0 and `x=2 pi` is "A" ,then `(A)/(pi^(2))` is .......

Similar Questions

Explore conceptually related problems

Find the area bounded by y=1+2 sin^(2)x,"X-axis", X=0 and x=pi .

The area of the region bounded by the curve y=x"sin"x, x-axis, x=0 and x=2pi is :

The area bounded by y=x|sin x| and x -axis between x=0,x=2 pi is

The area bounded by y = |sin x|, X-axis and the line |x|=pi is

Find the area bounded by the y-axis,y=cos x, and y=sin x when 0<=x<=(pi)/(2)

Find the area bounded by y = sin x and axis of x in (0 , pi)

The area bounded by y=tan x,y=cot x,x axis in 0<=x<=(pi)/(2) is

For 0<=x<=pi, the area bounded by y=x and y=x+sin x, is

Area bounded by the curve y=sin x between .x=0 and x=2 pi is

Find the area bounded by the curve y=sin x between x=0 and x=2 pi.