The potential difference E and current I flowing through the ac circuit is given by `E=5 cos (omega t -pi//6) V and I=10 sin (omega)t A`. Find the average power dissipated in the circuit.

The potential difference V across and the current I flowing through an instrument in an AC circuit are given by: V=5 cos omega t volt I=2 sin omega t Amp.

The potential difference V across and the current I flowing through an instrument in an AC circuit are given by: V=5 cos omega t volt I=2 sin omega t Amp.

The potential differences V and the current i flowing through an instrument in an AC circuit of frequency f are given by V=5 cos omega t and I=2 sin omega t amperes (where omega=2 pi f ). The power dissipated in the instrument is

The potential differences V and the current i flowing through an instrument in an AC circuit of frequency f are given by V=5 cos omega t and I=2 sin omega t amperes (where omega=2 pi f ). The power dissipated in the instrument is

The voltage and current in an a.c. circuit are given by E = 300 sin (omega t + pi//2) and I = 5 sin omega t . What is power factor of the circuit and power dissipated in each cycle ?

In an AC circuit, e and i are given by e = 150 sin 150 t V and i = 150 sin (150t+pi/3) A. The 1 power dissipated in the circuit is

For an ac circuit V=15 sin omega t and I=20 cos omega t the average power consumed in this circuit is