The horizontal and vertical displacements of a projectile at time t are `x = 36t and y = 48t -4.9t^2` respectively. lmtial velocity of the projectile in `ms^-1` is

The horizontal and vertical displacements of a projectile at time t are x=36t and y=48t-4.9t^(2) respectively where x ,y are in meters and t in seconds.Initial velocity of the projectile in m/s is

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x = 6t metre and y = 8t-5t^2 metre. The range of the projectile in metre is

The height y and distance x along the horizontal plane of a projectile on a certain planet are given by x = 6t m and y = (8t - 5t^(2))m . The velocity with which the projectile is projected is

The height y and distance x along the horizontal plane of a projectile on a certain planet are given by x = 6t m and y = (8t^(2) - 5t^(2))m . The velocity with which the projectile is projected is

The horizontal and vertical displacements of a particle moving along a curved line are given by x=5t and y = 2t^2 + t. Time after which its velocity vector makes an angle of 45^@ with the horizontal is