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Exchange rate of U.S. dollar vis-a -vis ...

Exchange rate of U.S. dollar vis-a -vis Indian rupee (i.e. 1 U.S. dollar = so many Rs) from April to Dec . 2002 is given below . Find the range and the coefficient of range.

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The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m . The projection velocity must be

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. From a certain tower of unknown height it is found that the maximum range at a certain projection velocity is obtained for a projection angle of 30^(@) and this range is 10sqrt(3)m . The projection velocity must be

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. A tower is at a distance of 5m from a man who can throw a stone with a maximum speed of 10m//s . What is the maximum height that the man can hit on this tower.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. A tower is at a distance of 5m from a man who can throw a stone with a maximum speed of 10m//s . What is the maximum height that the man can hit on this tower.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. In the previous problem, what should be the corresponding projection angle.

The trajectory of a projectile is given by y=x tantheta-(1)/(2)(gx^(2))/(u^(2)cos^(2)theta) . This equation can be used for calculating various phenomen such as finding the minimum velocity required to make a stone reach a certain point maximum range for a given projection velocity and the angle of projection required for maximum range. The range of a particle thrown from a tower is define as the distance the root of the tower and the point of landing. In the previous problem, what should be the corresponding projection angle.

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