Find the amount of energy produced in joules due to fission of 1 gram of uranium assuming that 0.1 percent of mass is transformed into energy.
Take 1amu=`1.66xx10^(-27)kg=931.5MeV`
Mass of uranium =235amu.
Avogadro number =`6.02xx10^(23)`

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

find the amount of energy produced in jaoules due to fission of 1 g of ""._(92)U^(235) assuming that 0.1% of mass is transormed into enengy ,Atomic mass of ""._(92)U^(235)=235 amu , Avogodro number N_(A)=6.023xx10^(23). Given that the energy released per fission is 200 MeV.

find the amount of energy produced in jaoules due to fission of 1 g of ""._(92)U^(235) assuming that 0.1% of mass is transormed into enengy ,Atomic mass of ""._(92)U^(235)=235 amu , Avogodro number N_(A)=6.023xx10^(23). Given that the energy released per fission is 200 MeV.

Show that energy equivalent of one atomic mass unit is nearly 933MeV . Take 1a m u=1.66xx10^(-27)kg

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 W of power is (Take leV = 1.6xx10^(-19)J)

In fission of one uranium-235 nucleus, the loss in mass is 0.2 a.m.u. Calculate the energy released.

If one a.m.u.= 1.66xx10^(-27)kg , when is the mass of one atom of C^(12) ?

If 190 MeV energy is released due to fission of each nucleus of U-235, what mass of U-235 undergoes fission per hour in a reactor of power 300 MW ? Take 1 a.m.u. = 1.66 xx 10^-27 kg .

Find the rest mass energy of a proton in MeV. [m_(p) = 1.673 xx 10^(-27) kg]