समीकरण `cos 2 theta = cos^(2) theta ` को हल कीजिए।

The value of the expression (cos^(6)theta + sin^(6) theta – 1) (tan^(2) theta + cot^(2) theta + 2) is: समीकरण (cos^(6)theta + sin^(6) theta – 1) (tan^(2) theta + cot^(2) theta + 2) का मान है:

Prove that cos 8 theta cos 2 theta = cos^(2) 5theta- sin^(2) 3 theta

If theta =(pi)/(2 ^(n) +1), then cos theta cos 2 theta cos 2^(2) theta …cos 2 ^(n-1)theta is equal to

cos ^(2) 2 theta - sin ^(2) theta = cos theta . cos 3 theta.

cos theta + cos 2 theta + cos 3 theta + …. + cos { (n-1) theta}+ cos n theta=

If theta = pi/(2^(n) + 1), "show that",2^(n) cos theta cos 2 theta cos2^(2) theta cos2^(3) theta.... cos2^(n-1) theta = 1.

If sin theta + sin^(2) theta =1 then cos^(4) theta + cos^(8) theta + 2 cos^(6) theta =

If cos theta =4/5 then sin^2 theta cos theta + cos^2 theta sin theta is equal to :

cos (2 theta) cos ((theta) / (2)) - cos (3 theta) cos ((9 theta) / (2)) = sin (5 theta) sin ((5 theta) / (2))

2 cos theta - cos 3 theta - cos 5 theta - 16 cos^(3) theta sin^(2) theta =