[A" force "bar(F)=(2hat i+hat j+3hat k)N" acts on a particle of mass "1kg" for "2s" .If initial velocity of particle is "],[u=(2hat i+hat j)m/s" .Speed of particle at the end of "2s" will be; "]

A force vec(F)=(2hat(i)+hat(j)+3hat(k)) N acts on a particle of mass 1 kg for t = 2s. If initial velocity of particle is vec(u)=(2hat(i)+hat(j))ms^(-1) , then the speed of particle at the t = 2 s will be

Velocity of a particle at some instant is v=(3hat i + 4hat j + 5hat k) m//s . Find speed of the particle at this instant.

Velocity of a particle at some instant is v=(3hat i + 4hat j + 5hat k) m//s . Find speed of the particle at this instant.

A uniform force of (3hat i + hat j) newtons acts on a particle of mass 2kg . Hence the particle is displaced from position (2 hat i+ hat k) meter to position (4hat i+ 3hatj-hatk) meter. The work done by the force on the particle is:

A force (hat(i)-2hat(j)+3hat(k)) acts on a particle of position vector (3hat(i)+2hat(j)+hat(k)) . Calculate the hat(j)^(th) component of the torque acting on the particle.

A particle has initial velocity (3 hat i+ 4 hat j) and has acceleration (0.1 hat i+ 0.3 hat j) . Its speed after 10 s is.

A uniform force of (2hat(i)+hat(j)) N acts on a particle of mass 1 kg. The particle displaces from position (3hat(j)+hat(k)) m to (5hat(i)+3hat(j)) m. The work done by the force on the particle is

A force (hat(i)-2hat(j)+3hat(k)) acts on a particle of position vector (3hat(i)+2hat(j)+hat(k)) . Calculate the torque acting on the particle.