If `V`, in the equation `Lambda_(eq.) = kappa xx V`, is the volume in `CC` constaining `1` eq. of the electrolyte, than `V` for a `N//10` solutions will be

If ’V’, in the equation, lambda = K xx V is the volume in cc containing 1gm equivalent of the electrolyte, ‘V’ for an N//10 solution will be-

For a very dilute solution, the osmotic pressure is given by pi = n_(2)RT//V where V is the volume in L containing n_2 moles of nonvolatile solute. Establish the equation for molar mass of solute.

If 1 mol of an electrolyte is dissolved in V cm^(3) of a solution, then molar conductivity of the solution is Lambda_(m) = conductivity of the solution xx V. If the concentration of the solution is (M)/(10), then find the value of V.

The ionization constant of a weak electrolyte is 25 xx 10^(-6) while the equivalent conductance of its 0.01 M solution is 19.6 s cm^(2) eq^(-1) . The equivalent conductance of the electrolyte at infinite dilution (in S cm^(2)eq^(-1) ) will be

The ionization constant of a weak electrolyte is 25 xx 10^(-6) while the equivalent conductance of its 0.01 M solution is 19.6 s cm^(2) eq^(-1) . The equivalent conductance of the electrolyte at infinite dilution (in S cm^(2)eq^(-1) ) will be