" 12."f(x)=(x-1)(x+2)^(2)

If f:R to R is defined by f(x)={{:(,(x-2)/(x^(2)-3x+2),"if "x in R-(1,2)),(,2,"if "x=1),(,1,"if "x=2):} "them " lim_(x to 2) (f(x)-f(2))/(x-2)=

If f:R to R is defined by f(x)={{:(,(x-2)/(x^(2)-3x+2),"if "x in R-(1,2)),(,2,"if "x=1),(,1,"if "x=2):} "them " lim_(x to 2) (f(x)-f(2))/(x-2)=

If f:R to R is defined by f(x)={{:(,(x-2)/(x^(2)-3x+2),"if "x in R-(1,2)),(,2,"if "x=1),(,1,"if "x=2):} "then " underset(x to 2)lim (f(x)-f(2))/(x-2)=

If f(x)=ln(x^(2)-x+2);R^(+)rarr R and g(x)={x}+1;[1,2]rarr[1,2], Find the domain and range of f(g(x)) when defined.

Verify the Rolle's theorem for f(x)=(x-1)^(2) in [1,2].

f(x)=-(1)/(3)x^(3)+5x^(2)+12

If f(x)=|[1,2(x-1),3(x-1)(x-2)],[x-1,(x-1)(x-2),(x-1)(x-2)(x-3)],[x,x(x-1),x(x-1)(x-2)]| . Then, the value of f(2020) is

Examine the continuity in (-2, 2) of f(x)=(x^2-x+12)/(x^2-8x+12)

f(x)=(x)/(x+1), [1,2]