int_(0)^(n/4)2tan x^(3)dx

int_(0)^( pi/4)tan^(3)dx

int_(0)^(pi//4)(tan^(3)x)/((1+cos2x))dx

I_(n)=int_(0)^(pi//4) tan^(n)x dx , where n in N Statement-1: int_(0)^(pi//4) tan^(4)x dx=(3pi-8)/(12) Statement-2: I_(n)+I_(n-2)=(1)/(n-1)

I_(n)=int_(0)^(pi//4) tan^(n)x dx , where n in N Statement-1: int_(0)^(pi//4) tan^(4)x dx=(3pi-8)/(12) Statement-2: I_(n)+I_(n-2)=(1)/(n-1)

If I_(n) = int_(0)^(pi//4) tan^(n) x dx then (1)/(I_(3)+I_(5))=

A:int_(0)^(pi//4)(tan^(6)x+tan^(4)x)dx=(1)/(5) R:int_(0)^(pi//4)(tan^(n)x+tan^(n-2)x)dx=(1)/(n-1)

int_(0)^(pi//4)(tan^(4)x+tan^(3)x)dx=

If I_(n)=int_(0)^(pi//4)tan^(n)x dx , where n ge 2 , then : I_(n-2)+I_(n)=

Evaluate : int_(0)^(pi//4) tan ^(2) x dx