" i) "y=3x^(2)-x+1" at "(1,3)

The equation of normal to the curve y=3x^(2)-x+1 at (1,3) is

The equation of tangent to the curve y=3x^(2)-x+1 at (1,3) is

Find the equation of the tangent to the curve y=3x^(2)-x+1 at P(1, 3).

The equation of tangent to the curve y =3 x^2 -x+ 1 at p (1, 3) is..... A) 5x-y=2 B) x+5y=16 C) 5x-y+2=0 D) 5x=y

Find the equation of tangent and normal to the curve y =3x^(2) -x +1 at the point (1,3) on it.

The solution of the differential equation x (dy)/(dx) + y = (1)/(x^(2)) at (1, 2) is a) x^(2)y + 1 = 3x b) x^(2)y + 1 = 0 c) xy + 1 = 3x d) x^(2) (y + 1) = 3x

The solution of (dy)/(dx) + (3x^(2) y)/(1 + x^(3)) = (1+ x^(2))/(1 + x^(3)) is

Evaluate : (x^(1//3)+y^(1//3))(x^(2//3)-x^(1//3)y^(1//3)+y^(2//3)) , when x=4(5)/(7) " and " y=5(2)/(7) .

If y=(x^(2//3)-x^(-1//3))/(x^(2//3)+x^(-1//3))," then "(x+1)^(2)y_(1)=