43. The magnetic field at O due to current in the infinite wire forming a loop as shown in Figure is BS 02 (a) Ho7 (cos, + cos2) (b) 2πd Mo 21 (tan 8, +tan 8,) 40 d Hol (sin Ø, +sing.) (a) cose,+ sine,) 40 d

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper . The distance of each wire from the centre of the loop is d . The loop and the wire are carrying the same current I . The current in the loop is in the counterclockwise direction if seen from above. (q) The magnetic fields(B) at P due to the currents in the wires are in opposite directions. (r) There is no magnetic field at P . (s) The wires repel each other. (4) When d~~a but wires are not touching the loop , it is found that the net magnetic field on the axis of the loop at a height h above the loop is zero. In that case

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper . The distance of each wire from the centre of the loop is d . The loop and the wire are carrying the same current I . The current in the loop is in the counterclockwise direction if seen from above. (q) The magnetic fields(B) at P due to the currents in the wires are in opposite directions. (r) There is no magnetic field at P . (s) The wires repel each other. (5) Consider dgtgta , and the loop is rotated about its diameter parallel to the wires by 30^(@) from the position shown in the figure. If the currents in the wire are in the opposite directions, the torque on the loop at its new position will be ( assume that the net field due to the wires is constant over the loop).

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper . The distance of each wire from the centre of the loop is d . The loop and the wire are carrying the same current I . The current in the loop is in the counterclockwise direction if seen from above. (q) The magnetic fields(B) at P due to the currents in the wires are in opposite directions. (r) There is no magnetic field at P . (s) The wires repel each other. (5) Consider dgtgta , and the loop is rotated about its diameter parallel to the wires by 30^(@) from the position shown in the figure. If the currents in the wire are in the opposite directions, the torque on the loop at its new position will be ( assume that the net field due to the wires is constant over the loop).

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper . The distance of each wire from the centre of the loop is d . The loop and the wire are carrying the same current I . The current in the loop is in the counterclockwise direction if seen from above. (q) The magnetic fields(B) at P due to the currents in the wires are in opposite directions. (r) There is no magnetic field at P . (s) The wires repel each other. (4) When d~~a but wires are not touching the loop , it is found that the net magnetic field on the axis of the loop . In that case

The figure shows a circular loop of radius a with two long parallel wires (numbered 1 and 2) all in the plane of the paper . The distance of each wire from the centre of the loop is d . The loop and the wire are carrying the same current I . The current in the loop is in the counterclockwise direction if seen from above. (q) The magnetic fields(B) at P due to the currents in the wires are in opposite directions. (r) There is no magnetic field at P . (s) The wires repel each other. (4) When d~~a but wires are not touching the loop , it is found that the net magnetic field on the axis of the loop . In that case

According to Biot-Savarat's law, magentic field due to a straight current carrying wire at a point at a distance r form it is given by B=(mu_0I)/(4pir)(sinphi_1+sinphi_2) The direction of magnetic field being perpendicular to the plane containing the wire and the point. Figure, shows a closed loop AOCBA in which current I is flowing as shown. Given OA=OB=OC=a . Find the magnetic field at point B due to this loop.

According to Biot-Savarat's law, magentic field due to a straight current carrying wire at a point at a distance r form it is given by B=(mu_0I)/(4pir)(sinphi_1+sinphi_2) The direction of magnetic field being perpendicular to the plane containing the wire and the point. Figure, shows a closed loop AOCBA in which current I is flowing as shown. Given OA=OB=OC=a . Find the magnetic field at point B due to this loop.

The magnetic field through a single loop of wire, 12 cm in radius and of 8.5Omega resistance, changes with time as shown in figure. Calculate the emf in the loop as a function of time. Consider the time intervals (a) t = 0 to t =2.0 s (b) t =2.0 s to t =4.0 s (c) t =4.0 s to t =6.0 s . The magnetic field is perpendicular to the plane of the loop.