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[" Solution of "0.1NNH(4)OH" and "0.1N],...

[" Solution of "0.1NNH_(4)OH" and "0.1N],[NH_(4)Cl" has "pH9.25" ,then find out "],[pK_(b)" of "NH_(4)OH]

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Solution of 0.1 N NH_(4)OH and 0.1 N NH_(4)Cl has pH 9.25 , then find out pK_(b) of NH_(4)OH .

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A solution consist of 0.2 M NH_(4)OH and 0.2 M NH_(4)Cl . If K_(b) of NH_(4)OH is 1.8 xx 10^(-5) , the [OH^(-)] of the resulting is