Velocity and acceleration of a particle at time t = 0 are `u=(2hat(i)+3hat(j))m//s` and `a=(4hat(i)+2hat(j))m//s^(2)` respectively. Find the velocity and displacement of particle at t = 2 s.

At a particular instant velocity and acceleration of a particle are (-hat(i)+hat(j)+2hat(k))m//s and (3hat(i)-hat(j)+hat(k))m//s^(2) respectively at the given instant particle's speed is :

At a particular instant velocity and acceleration of a particle are (-hat(i)+hat(j)+2hat(k))m//s and (3hat(i)-hat(j)+hat(k))m//s^(2) respectively at the given instant particle's speed is :

The velocity and acceleration vectors of a particle undergoing circular motion are v = 2 hat(i) m//s and a = 2 hat(i)+4 hat(j)m//s^(2) respectively at some instant of time. The radius of the circle is

The velocity and acceleration vectors of a particle undergoing circular motion are v = 2 hat(i) m//s and a = 2 hat(i)+4 hat(j)m//s^(2) respectively at some instant of time. The radius of the circle is

A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are a=(4 hat(i)+3hat(j))m//s^(2) and p=(8 hat(i)-6hat(j))"kg-m/s" . The motion of the particle is

A particle has initial velocity of (3hat(i)+4hat(j)) m//s and a acceleration of (4hat(i)-3hat(j)) m//s^(2) . Its speed after one second will be equal to :-

A particle has initial velocity of (3hat(i)+4hat(j)) m//s and a acceleration of (4hat(i)-3hat(j)) m//s^(2) . Its speed after one second will be equal to :-

A particle has initial velocity of (3hat(i)+4hat(j)) m//s and a acceleration of (4hat(i)-3hat(j)) m//s^(2) . Its speed after one second will be equal to :-

A particle starts with an initial veloctiy (hat(i) + hat(j)) m//s and changes it to (3 hat(i) - 5 hat(j)) m//s in 2 sec. What is the magnitude of displacement of the particle in 2s, if the acceleration is constant ?