If `K_(h)` (hydrolysis constant) for anilinium ion is `2.4xx10^(-5) M`, then `K_(b)` for aniline will be

The hydrolysis constant of NaX ( K_a of HX is 2xx 10 ^(-6)) is

The hydrolysis constant of NaX ( K_(a) of HX is 2 xx 10^(-6) ) is

The Hydrolysis constant of MX is (Given, K_(b) of MOH is 2 xx 10^(-6) and K_(a) of HX is 5 xx 10^(-7) )

Calculate the hydrolysis constant for 0.1 M sodium acetate solution. (K_a=1.8xx10^(-5))

Calculate the hydrolysis constant of the salt containing NO_(2)^(-) . Given the K_(a) " for " HNO_(2) = 4.5 xx 10^(-10)

Calculate the hydrolysis constant of the salt containing NO_(2)^(-) . Given the K_(a) " for " HNO_(2) = 4.5 xx 10^(-10)