Home
Class 12
CHEMISTRY
Equilibrium constant K(p) for the reacti...

Equilibrium constant `K_(p)` for the reaction `CaCO_(3)(s) hArr CaO(s) + CO_2(g)` is 0.82 atm at `727^@C`.
If 1 mole of `CaCO_(3)` is placed in a closed container of 20 L and heated to this temperature, what amount of `CaCO_(3)` would dissociate at equilibrium?

Promotional Banner

Similar Questions

Explore conceptually related problems

For the reaction CaCO_(3(s)) hArr CaO_((s))+CO_(2(g))k_p is equal to

For the reaction CaCO_(3(s)) hArr CaO_((s))+CO_(2(g))k_p is equal to

For the reaction CaCO_(3)(s) hArr CaO(s) + CO_(2)(g) K_(p)=1.16 atm at 800^(@)C . If 20.0g of CaCO_(3) was put into a 10.0 L flask and heated to 800^(@)C, what percentage of CaCO_(3) would remain unreacted at equilibrium ?

At 27^(@)C, K_(p) value for the reaction CaCO_(3)(s) hArr CaO (s) + CO_(2)(g) , is 0.1 atm. K_(C) value for this reaction is

At 27^(@)C, K_(p) value for the reaction CaCO_(3)(s) hArr CaO (s) + CO_(2)(g) , is 0.1 atm. K_(C) value for this reaction is

At 27^(@)C, K_(p) value for the reaction CaCO_(3)(s) hArr CaO (s) + CO_(2)(g) , is 0.2 atm. K_(C) value for this reaction is

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..

For CaCO_(3)(s) hArr CaO(s)+CO_(2)(g), K_(c) is equal to …………..