`10 "mole of" kSO_(2)` and `15 "mole of" O_(2)` were passed over catalyst to produce `8 "mole of" SO_(3)`. The ratio of `SO_(2)` and `SO_(3)` moles in mixture is:

When a mixture of 10 moles of SO_(2) and 15 moles of O_(2) was passed over catalyst, 8 moles of SO_(3) was formed. How many moles of SO_(2) and O_(2) did not enter into combination?

When a mixture of 10 moles of SO_(2) and 15 moles of O_(2) was passed over catalyst, 8 moles of SO_(3) was formed. How many moles of SO_(2) and O_(2) did not enter into combination?

When a mixture of 10 moles of SO_(2) and 15 moles of O_(2) was passed over catalyst, 8 moles of SO_(3) was formed. How many moles of SO_(2) and O_(2) did not enter into combination?

When a mixture of 10 moles of SO_(2) and 16 moles of O_(2) were passed over a catalyst, 8 moles of SO_(3) were formed at equilibrium. The number of SO_(2) and O_(2) remaining unreacted were:

10 moles SO_(2) and 15 moles O_(2) were allowed to react over a suitable catalyst. 8 moles of SO_(3) were formed. The remaining moles of SO_(2) and O_(2) respectively are -

When a mixture consisting of 10 moles of SO_2 and 16 moles of O_2 were passed over a catalyst , 8 mole of SO_3 were formed at equilibrium.The number of moles of SO_2 and O_2 which did not enter into reation were :

A container contains O_(2) , He and SO_(2) gases such that mass of SO_(2) is double the mass of O_(2) and mass of He is half the mass of O_(2) gas. The mole fraction of SO_(2) gas in the mixture is:

What volume of O_(2) is liberated when 3 moles of SO_(2) reacts with sufficient volume of O_(3)