Home
Class 11
PHYSICS
[" 27.The angle made by the string of a ...

[" 27.The angle made by the string of a simple "],[" pendulum with the vertical depends on time as "theta],[=(pi)/(90)sin[(pi5^(-1))t]" .Find the length of the pendulum "],[" If "g=pi^(2)m/s^(2)]

Promotional Banner

Similar Questions

Explore conceptually related problems

The angle made by the string of a simple pendulum with the vertical depends on time as theta=pi/90sin[(pis^-1)t] . Find the length of the pendulum if g=pi^2ms^-2

The angle made by the string of a simple pendulum with the vertical depends on time as theta=pi/90sin[(pis^-1)t] . Find the length of the pendulum if g=pi^2ms^-2

The angle made by the string of a simple pendulum with the vertical depends on time as theta=pi/90sin[(pis^-1)t] . Find the length of the pendulum if g=pi^2ms^-2

Instantaneous angle (in radian) between string of a simple pendulum and verical is given by theta = (pi)/(180) sin2pit . Find the length of the pendulum if g = pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g = pi^(2) m//s^(2) .

Find the length of seconds pendulum at a place where g =4 pi^(2) m//s^(2) .

Figure shown the kinetic energy K of a pendulum versus. its angle theta from the vertical. The pendulum bob has mass 0.2kg The length of the pendulum is equal to (g = 10m//s^(2)) ,

Calculate the time period of a simple pendulum of length one meter. The acceleration due to gravity at the place is pi^2ms^-2 .