" Got it "cos3xquad =quad cos2x

General solution of cos3x=cos2x is

Prove the following: (cos4x + cos3x + cos2x)/(sin4x + sin 3x + sin 2x)= cot 3x

Find the general solution: cos3x+cos x-cos2x=0

Evaluate: int cos x cos2x cos3xdx

int(sin x)/(cos3x*cos2x)dx

cosx + cos2x + cos3x=0

Solve the following: cos3x-cos2x=sin3x

1+ cos 2x+ cos4x + cos 6x= ............. A) 2 cos x cos 2x cos 3x B) 4 sin x cos 2x cos 3x C) 4 cos x cos 2x cos 3x D) 2 sin x cos 2x cos 3x

Prove that 1 + cos 2x + cos 4x + cos 6x = 4 cos x cos 2x cos 3x