The inverse of a matrix `A=[[a, b], [c, d]]` is

The inverse of the matrix {:[(a,b),(c,d)]:} is

Find the inverse of the matrix A = [(a,b),(c,d)] . Given that ad - bc ne 0

If the inverse of the matrix [[1,2],[3,-5]]^(n) is 1/11[[a,b],[c,d]] , then the ascending order of a, b, c, d is

The inverse of the matrix [[1 , 0, 0],[ a , 1 , 0],[ b, c , 1]] is

Find the inverse of the matrix A=[(a, b),( c,(1+b c)/a)] and show that a A^(-1)=(a^2+b c+1)I-a A .

If a, b, c are non-zero real numbers, then the inverse of the matrix A [[a,0,0],[0,b,0],[0,0,c]] is

If ({:(e, f),(g,h):}) is the inverse of the matrix ({:(a, b),(c,d):}) where ad-bc =1, then g equals

If the inverse of the matrix [(1,2),(3,-5)] is 1/11[(a,b),(c,d)] then the ascending order of a,b,c,d is

Find the inverse of the matrix : A = {:[(a,b),(c,(1+bc)/a)] .

Using elementary transformation, find the inverse of the matrix A=[(a,b),(c,((1+bc)/a))] .