A proton is travelling with horizontal velocity `v_x=2*5xx10^8cms^-1`. Calculate the transverse deflection in travelling horizontal distance, `x=5cm` in electric field of `E_y=400V//cm`. Mass of proton, `m=1*6xx10^(-24)g`, charge on proton, `e=1*6xx10^(-19)C`.

The maximum kinetic energy of protons in a cyclotron of radius 0.4 m in a magnetic field of 0.5 T is (mass of proton = 1.67 xx 10^(-27) kg, charge of proton = 1.6 xx 10^(-19) C)

The maximum kinetic energy of protons in a cyclotron of radius 0.4 m in a magnetic field of 0.5 T is (mass of proton = 1.67 xx 10^(-27) kg, charge of proton = 1.6 xx 10^(-19) C)

Calculate the magnitude and direction of the electric field. Which keeps a proton just floating. Give that mass of proton 1.67 xx 10^-27 kg, charge on proton = 1.6 xx 10^-19 C and g = 9.8 ms^-2

If the maximum value of accelerating potential provided by a radio frequency oscillator be 10kV , calculate the number of revolutions made by an alpha -particle in a cyclotron to achieve one-tenth of the speed of light. Mass of proton =1*67xx10^(-27)kg , charge on proton =1*6xx10^(-19)C .

A proton is projected with a velocity 10^(7)ms^(-1) , at right angles to a uniform magnetic field of induction 100mT . The time ( in second ) taken by the proton to traverse 90^(@) are is : ( Mass of proton =1.65xx10^(-27)kg an charge of proton =1.6 xx10^(-19)C)

The intensity of electric field required to balance a proton of mass 1.7xx10^-27 kg and charge 1.6xx10^-19 C is nearly

The figure shows a region of length ‘l’ with a uniform magnetic field of 0.3 T in it and a proton entering the region with velocity 4xx10^(5) " ms"^(-1) making an angle 60^(@) with the field. If the proton completes 10 revolution by the time it cross the region shown, ‘l’ is close to (mass of proton = 1.67 xx10^(27) kg , charge of the proton =1.6 xx10^(-19) C )

The figure shows a region of length ‘l’ with a uniform magnetic field of 0.3 T in it and a proton entering the region with velocity 4xx10^(5) " ms"^(-1) making an angle 60^(@) with the field. If the proton completes 10 revolution by the time it cross the region shown, ‘l’ is close to (mass of proton = 1.67 xx10^(-27) kg , charge of the proton =1.6 xx10^(-19) C )

A beam of protons with a velocity 4 xx 10^(5) m/sec enters a uniform magnetic field of 0.3 Testa at an angle of 60^(@) to the magnetic field. Find the radius of the helical path taken by the proton beam. Also find the pitch of the helix, which is the distance travelled by a proton in the beam parallel to the magnetic field during one period of rotation [Mass of proton = 1.67 xx 10^(-27) kg. charge on proton = 1.6 xx 10^(19)C ]