`int(1)/(x^(2)-5x+6)dx`

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int(1)/(2x^(2)+5x+3)dx

int(x+1)/(x^2+5x+6)dx=

Evaluate int(x^(2)+1)/(x^(2)-5x+6)dx

integrate this int(x^(2)+1)/(x^(2)-5x+6)dx

int(x^(2))/(x^(2)-5x+6)dx=

int(1)/(6+5x-6x^(2))dx

(3) int(x^(2)+5x+6)dx

int_(2)^(3)(1)/(x^(2)+5x+6)dx =

int(dx)/((x^(2)+5x+6)sqrt(x+1))

(3) int(x^(2)-5x+6)/(x-3)dx