The eccentricity of an ellipse whose centre is at the origin is `1/2dot` if one of its directrices is `x=-4,` then the equation of the normal to it at `(1,3/2)` is: `4x+2y=7` (2) `x+2y=4` (3) `2y-x=2` (4) `4x-2y=1`

The eccentricity of an ellipse whose centre is at the origin is (1)/(2) .If one of its directrices is x=-4, then the equation of the normal to it at (1,3) is :

The eccentricity of an ellipse whose centre is at the origin is (1)/(2) .if one of its directrices is x=-4, then the equation of the normal to it at (1,(3)/(2)) is: 4x+2y=7(2)x+2y=4(3)2y-x=2(4)4x-2y=1

The eccentricity of an ellipse with its centre at the origin is (1)/(2) . If one of the directrices is x = 4 , then the equation of ellipse is

The equation of the normal at (1,2) to the circle x^(2)-y^(2)-4x-6y-12=0 is

The eccentricity of the ellipse x^(2)+4y^(2)+8y-2x+1=0 , is

The eccentricity of ellipse 4(x-2y+1)^2 +9(2x+y+2)^2=180 is

An ellipse is drawn by taking a diameter of the circle (x""""1)^2+""y^2=""1 as its semiminor axis and a diameter of the circle x^2+""(y""""2)^2=""4 as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is (1) 4x^2+""y^2=""4 (2) x^2+""4y^2=""8 (3) 4x^2+""y^2=""8 (4) x^2+""4y^2=""16