In a circuit potential difference across resistence `V = (4 +- 0.25)V `and curent in resistence ,`f = (1 +- 0.1)` what is the value of resistence with its percentage error

The resistance of a metal is given by R = V//I , where V is potential difference and I is current . In a circuit , the potential difference across resistance is V = ( 8 +- 0.5) V and current in resistance , I = ( 4 +- 0.2)A . What is the value of resistance with its percentage error?

The resistance of a metal is given by R = V//I , where V is potential difference and I is current . In a circuit , the potential difference across resistance is V = ( 8 +- 0.5) V and current in resistance , I = ( 4 +- 0.2)A . What is the value of resistance with its percentage error?

The resistance of a metal is given by R=(V)/(I), where V is potential difference and I is the current. In a circuit the potential difference across resistance is V=(8+-0*5) V and current in resistance, I=(4+-0*2)A . And current in resistance with its percentage error :

The resistance of metal is given by V = IR , The voltage in the resistance is V = (8 pm 0.5)V and current in the resistance is I = (2 +- 0.2)A , the value fo resistance with its percentage error is

The resistance of metal is given by V = IR , The voltage in the resistance is V = (8 pm 0.5)V and current in the resistance is I = (2 +- 0.2)A , the value fo resistance with its percentage error is

The voltage measured across resistance is V = (50 pm 0.1)V and current is I = ( 10 pm 0.2) . Find error in resistance

Give, potential difference V = (8 + 0.5) V and current I = (2 + 0.2) A. The value of resistance R is

Give, potential difference V = (8 + 0.5) V and current I = (2 + 0.2) A. The value of resistance R is

In an electric circuit, potential difference across a lamp is 20 V and current through the lamp is 0.5A. The resistance of the lamp is

In the given circuit, if the potential difference across the internal resistance r_1 is equal to E, then the resistance R is equal to: