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निम्न समीकरणों को पूरा कीजिएः .(90)Th^...

निम्न समीकरणों को पूरा कीजिएः
`._(90)Th^(234)to._(91)Pa^(234)+…………+…………..`

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Complete the reaction : ""_90Th^(234) to ""_91Pa^(234) +?

Part of uranium decay series is shown ._(92)U^(234) to ._(90)Th^(234) to ._(91) Pa^(234) to ._(90)Th^(230) to ._(88)Ra^(226) How many parts of isotopes are there in the above series

Part of uranium decay series is shown ._(92)U^(234) to ._(90)Th^(234) to ._(91) Pa^(234) to ._(90)Th^(230) to ._(88)Ra^(226) How many parts of isotopes are there in the above series

The radioactive nuclei are unstable and emit alpha (._(2)He^(4)) , beta (._(-1)e^(0)) and gamma (._(0)gamma^(0)) radiations to acheive states of greater stability. Rutherford and Soddy suggested the following rules governing the radioactive decay, (i) The algebric sum of charges (atomic numbers) before and after disintegration must be the same. (ii) The sum of mass numbers before and after disintegration must also be the same. The particle emitted in the reaction ._(90)Th^(234) to ._(91)Pa^(234)+........ is

An isotope ._(92)U^(238) decays successively to form ._(90)Th^(234),._(91)Pa^(234),._(90)Th^(234),._(90)Th^(230) and ._(88)Ra^(226) . What are the radiations emitted in these five steps?

In the nuclear reaction ._(90)^(234)Th rarr ._(91)^(234)Pa + X . X is -

How many alpha and beta particles will be emitted when ._(90)Th^(234) change into ._(84)Po^(218) ?

An isotope _(92)U^(238) decays successively to form _(90)Th^(234),_(91)Pa^(234),_(92)U^(234),_(90)Th^(230) and _(88)Ra^(226) .What are the radiation emitted in these five steps?

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