If `k_1=tan 27 theta-tan theta and k_2=(sintheta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)`then,

If a=tan27theta-tanthetaand b=(sin theta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta), then

If k_(1)=tan27 theta-tan theta and k_(2)=(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)

If A= tan27theta - tantheta and B= (sintheta)/(cos 3theta) +(sin 3theta)/(cos 9theta) + (sin 9theta)/(cos 27theta) , then the value of (A+B)/(A-B) +(A-B)/(A+B) -10/3 is

If A= tan27theta - tantheta and B= (sintheta)/(cos 3theta) +(sin 3theta)/(cos 9theta) + (sin 9theta)/(cos 27theta) , then the value of (A+B)/(A-B) +(A-B)/(A+B) -10/3 is

x= tan 27 theta - tan theta , y=(sin theta )/( cos 3 theta )+(sin 3 theta )/(cos 9theta)+(sin9 theta )/(cos 27 theta ) , if

(sin theta)/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)+(sin27theta)/(cos81theta)=

Prove that sintheta/(cos3theta)+(sin3theta)/(cos9theta)+(sin9theta)/(cos27theta)=1/2(tan27theta-tantheta)

(sin theta)/(cos3 theta)+(sin3 theta)/(cos9 theta)+(sin9 theta)/(cos27 theta)+(sin27 theta)/(cos81 theta)=

Show that, (sin theta)/(cos 3 theta) + (sin 3 theta)/(cos 9 theta) + (sin 9 theta)/(cos 27 theta) = 1/2 ( tan 27 theta - tan theta).

Integration using rigonometric identities : int(sin theta)/(cos3 theta)+(sin 3 theta)/(cos9 theta)+( sin9 theta)/(cos 27theta)d theta=...+c