[" 11."2[(16-15)^(-1)+25(13-8)^(-2)]^(-1)+(1024)^(0)=],[[" (a) "2," (b) "3],[" (c) "1," (d) "5]]

The value of (1-(1)/(3^(2)))(1-(1)/(4^(2)))(1-(1)/(5^(2)))ddot M(1-(1)/(11^(2)))(1-(1)/(12^(2))) is (11)/(20) (b) (13)/(15) (c) (13)/(18) (d) (15)/(16) (e) None of these

3(5a-7)-2(9a-11)=4(8-13-1)

[(7,1,5),(8,0,0)] [(2),(3),(1)] +5 [(1),(0)] is equal to a) [(16),(27)] b) [(27),(16)] c) [(15),(16)] d) [(16),(15)]

1-(1)/(8)+(1.3)/(8.16)-(1.3.5)/(8.16.24)+…..=

Sum of first 10 terms of the series, S= (7)/(2 ^(2)*5 ^(2)) + (13)/(5 ^(2)*8 ^(2)) + (19)/(8 ^(2) *11^(2))+ …… is : (a) (255)/(1024) (b) (88)/(1024) (c) (264)/(1024) (d) (85)/(1024)

2 ^(16-log_(2)1024) = ______

I. x = (1024)^(1//2) II. y^(2) = 1024

The inverse of the matrix A[(1,1,1),(6,7,8),(6,7,-8)] using adjoint method is ...a) -(1)/(16)[(-112,1,15),(96,-14,-2),(0,-1,1)] b) -(1)/(16)[(-112,15,1),(96,-2,-14),(0,-1,1)] c) -(1)/(16)[(-112,15,1),(96,-14,-2),(0,-1,1)] d) -(1)/(16)[(112,15,1),(96,-14,-2),(-1,0,1)]

Simplify: 1/(1+(2/3)/(1+2/3+(8/9)/(1-2/3))) . (11)/(13) (b) (13)/(15) (c) (13)/(11) (d) (15)/(13)