The bob of a simple pendulum of length L, is displaced through `90^(@)`, from its mean position and then released. What will be the tension in the string when the bob of mass m will be its lowest position ?

The bob of a simple pendulum of length L, is displaced through 90^(@) , from its mean position and then released. What will be the tension in the string when the bob of mass m will be at its lowest position?

A pendulum bob of mass m is displaced through an angle theta from its equilibrium position and then released. What will be the tension in the string when the bob crosses the equilibrium position?

Mass of the bob of a simple pendulum of length L is m . If the bob is projected horizontally from its mean position with velocity sqrt(4 gL) , then the tension in the string becomes zero after a vertical displacement of

The bob of a simple pendulum of length 1 m is' pulled aside from its equilibrium’ position through an angle 60^@ and released. Calculate the speed at which the bob passes the equilibrium position.

The string of pendulum of length l is displaced through 90^@ from the vertical and released . Then the minimum strength of string in order to withstand the tension , as the pendulum passes through the mean position is

The string of pendulum of length l is displaced through 90^(@) from the vertical and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is

The string of pendulum of length l is displaced through 90^(@) from the vertical and released. Then the minimum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is

Mass of the bob of a simple pendulum is 10g and the effective length is 13 cm. The bob is pulled 5 cm away from the vertical and then released. What will be the kinetic energy of the bob when it passes through the lowest point?