Show that the relative error in the volume of a sphere, due to an error in measuring the diameter, is three times the relative error in the diameter.

Show that the relative error in the volue of a sphere due to an error in measurement of radius is thhree times the relative error in radius.

Show that the relative error in computing the volume of a sphere, due to an error in measuring the radius, is approximately equal to three times the relative error in the radius.

Show that the relative error in computing the volume of a sphere, due to an error in measuring the radius, is approximately equal to three times the relative error in the radius.

Show that the relative error in computing the volume of cube, due to an error in measuring its edge, is approximately equal to three times the relative error in the edge.

The percentage error in measuring the radius of a sphere is 1%. If S_(1) = percentage error in volume of the sphere, S_(2) = percentage error in surface area of the sphere, S_(3) = relative error in the diameter of the sphere then arrange S_(1) S_(2) S_(3) according to the values in ascending order

In a circle the relative error in the area is ...times the relative error in its circumference

Show that the relative error in the n^(th) power of a number is 'n' times the relative error in that number

The percentage error in surface area of a sphere is 6% then find the relative error in volume

Define relative error and percentage error.

The error in the measument of radius of a sphere is 0.4% . The relative error in its volume is