[" For "x in(0,(pi)/(2))" identify which is greater "(2sin x+tan x)or(3x)" .Hence find "lim_(x rarr0^(+))[(3x)/(2sin x+tan x)]" where "],[" [.] denotes the GIF."]

For x in (0, pi/2) identify which is greater (2 sin x + tan x ) or (3x) . Hence find {:(" "lim),(x rarr0):} [(3x)/(2sinx+tanx)] where [**] denote the greatest integer function.

lim_ (x rarr0 ^ (+)) (sin x) ^ (tan x)

lim_(x rarr0)(tan x)/(sin^(2)x)

lim_(x rarr0)(sin2x+3x)/(2x+tan3x)

. lim_(x rarr0)(x^(2))/(sin x^(2))

lim_(x rarr0)(tan2x-x)/(3x-sin x)

lim_(x rarr0)(x-sin x)/(tan^(2)x) .

lim_(x rarr0)[(x^(2))/(tan x*sin x)]

lim_(x rarr 0) (1-cos 5x)/(sin3x . tan 2x) =

lim_(x rarr0)x^(2)sin(pi/x)=