f(x)={[sin x-cos x,,x!=0],[-1,,x=0]

Examine the continuity of f ,where f is defined by f(x)={sin x-cos x,quad if x!=0;-1, if x=0

If f(x) is continuous at x=0 , where f(x)=sin x-cos x , for x!=0 , then f(0)=

If f(x)={[(cos x)^((1)/(sin x)),,x!=0],[K,,x=0]} is differentiable at x=0 Then K=

If f(x) = sin x - cos x , x != 0 , is continuous at x = 0, then f(0) is equal to

If f(x) = sin x - cos x , x != 0 , is continuous at x = 0, then f(0) is equal to

If f(x)={sin x,x<0 and cos x-|x-1|,x<=0 then g(x)=f(|x|) is non-differentiable for

Show that the function f(x) given by f(x)={(sin x)/(x)+cos x,x!=0 and 2,x=0 is continuous at x=0

Examine the continuity of f, where f is defined by f(x)= {(sin x- cos x",","if" x ne 0),(-1,"if" x = 0):}

Examine the continuity of f, where f is defined by f(x)={{:(sin x-cos x," if "x ne 0),(-1," if "x= 0):} .

Examine the continuity of f, where f is defined by f(x)={{:(sin x-cos x," if "x ne 0),(-1," if "x= 0):} .