A `1 kg` mass at rest is subjected to an acceleration of `5m//s^(2)` and travels `40 m`. The average power during the motion is

The velocity-time graph of a particle moving along a straight line is shown is . The rate of acceleration and deceleration is constant and it is equal to 5 m s^(-2) . If the a average velocity during the motion is 20 m s^(-1) , Then . The value of t is.

The velocity-time graph of a particle moving along a straight line is shown is . The rate of acceleration and deceleration is constant and it is equal to 5 m s^(-2) . If the a average velocity during the motion is 20 m s^(-1) , Then . The value of t is.

If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m//s^(2) , how long will it take to come to rest ?

The velocity-time graph of a particle moving along a straight line is shown is Fing. The rate of acceleration and deceleration is constant and it is equal to 5 m s^(-2) . If the a average velocity during the motion is 20 m s^(-1) , Then . The distace travelled with uniform velcoty is .

The velocity-time graph of a particle moving along a straight line is shown is Fing. The rate of acceleration and deceleration is constant and it is equal to 5 m s^(-2) . If the a average velocity during the motion is 20 m s^(-1) , Then . The distace travelled with uniform velcoty is .

A car of mass 1000 kg accelerates uniformly from rest to a velocity of 15 m/s in 5 sec. The average power of the engine during this period in watts is :

A body moving along a straight line travels one third of the total distance with a speed of 3.0 m s^(-1) . The remaining distance is covered with a speed of 4.0 m s^(-1) for half the time and 5.0 m s^(-1) for the other half of the time. The average speed during the motion is

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.