[" If the function "],[qquad f(x)={[1+sin(pi x)/(2)," for "-oo

If the function f(x) = {(1+sin((pi x)/2),",","for"-oo lt x le 1),(ax+b, ",","for" 1 lt x lt 3),(6tan((pi x)/12),",","for"3 le x lt 6):} is continuous in the interval (-oo, 6) , then the value of a and b are respectively

If the function f(x) = {(1+(sin)(pi x)/2,",","for"-oo lt x le 1),(ax+b, ",","for" 1 lt x lt 3),(6(tan)(pi x)/12,",","for"3 le x lt 6):} is continuous in the interval (-oo, 6) , then the value of a and b are respectively

The domain of the function f(x) = sin ^(-1) ((|x| +5)/(x^2 +1)) is ( -oo , -a ] uu [ a,oo ). then a is equal to :

The range of the function f(x)=(sin(pi[x]))/(x^(2)+1) (Where [ ] denotes greatest integer function) is (A) {0} (B) (-oo,oo) (C) (0,1) (D) R-{0}

The greatest value of the function f(x)=(sin2x)/(sin(x+(pi)/(4))) on the interval [0,(pi)/(2)] is

Find the domian and range of the function f (x) = (tan pi [x])/(1 + sin pi [x] + [x ^(2)])

The interval of increase of the function f(x)=x-e^(x)+tan(2 pi/7) is (a) (0,oo)(b)(-oo,0)(c)(1,oo)(d)(-oo,1)

The interval of increase of the function f(x)=x-e^x+tan(2pi//7) is (a) (0,\ oo) (b) (-oo,\ 0) (c) (1,\ oo) (d) (-oo,\ 1)

If function f(x) = (1+2x) has the domain (-(pi)/(2), (pi)/(2)) and co-domain (-oo, oo) then function is