The de Broglie wavelength `lambda` of a particle

In what way de - Broglie wavelength lambda of a particle is related to K.E?

de-Broglie wavelength lambda is

A particle of charge q, mass m and energy E has de-Broglie wavelength lambda . For a particle of charge 2q, mass 2m and energy 2E, the de-Broglie wavelength is

Two particles move at right angle to each other.Their de Broglie wavelengths are lambda_(1) and lambda_(2) respectively.The particles suffer perfectly inelastic collision.The de Broglie wavelength lambda of the final particle is given by :

A particle of charge q mass m and energy E has de-Broglie wave length lambda .For a particle of charge 2q mass 2m and energy 2E the de-Broglie wavelength is

State how de-Broglie wavelength (lambda) of moving particles varies with their linear momentum (P).

The de-Broglie wavelength (lambda) of a material particle of momentum (p) is given by

Two particles having de-Broglie wavelengths lambda_(1) and lambda_(2) , while moving along mutually perpendicular directions, undergo perfectly inelastic collision. The de-Broglie wavelength lambda , of the final particle is