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[sin48^(@)sec42^(@)+cos48^(@)cos ec42^(@...

[sin48^(@)sec42^(@)+cos48^(@)cos ec42^(@)=],[1)0quad " 2) "2quad " 3) "1quad 4" - "1]

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sin48^(@)sec42^(@)+cos48^(@)csc42^(@)=

sin42^(@)sec48^(@)+cos42^(@)cos ec48^(@)=2

cos48^(@)*cos12^(@)=

cos48^(@)*cos12^(@)=

cos48^(@)cos23^(@)cos ec42^(@)cos ec67^(@)=1

(sin48^(@))/(cos42^(@))+(cos48^(@))/(sin42^(@))=2

Show that: sin 42^(@)sec 48^(@)+cos 42^(@)cosec 48^(@)=2

(sin9^(@)-cos9^(@))/(sin48^(@)sin 12^(@))=

((sin48^(@))/(cos42^(@)))+((cos48^(@))/(sin42^(@)))=2

Evalute (c ) cos48^(@)-sin42^(@)